Tasks and exercises, 00001

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Re: Tasks and exercises, 00001

Beitrag von davidvajda.de »

written down by heart:

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Flour - F: Flora
Chlorine - Cl: Chlora
Oxygen - O - Oxa
Sulfur - S - Tia
Nitrogen - N Aza
Phosphorus - P - Phospha

         unsaturated saturated
3-Ring Irish Iran
4-Ring et etan
5-ring ol olan
6-ring in on
7-ring epin epan
8-ring ozin ozan

azirene, aziret, azirol, azirin, azepine, azonin, azezin

carbohydrates
1
2a 2b
3a 3b 3c 3d
4a 4b 4c 4d 4e 4f 4g 4h

CHO, CH2OH

1 H-C-OH
2 H-C-OH, H-C-OH
3 H-C-OH, H-C-OH, H-C-OH

2a H-C-OH, H-C-OH
2b H-C-OH, OH-C-H

3a H-C-OH, H-C-OH, H-C-OH
3b OH-C-H, H-C-OH, H-C-OH
3c H-C-OH, OH-C-H, H-C-OH
3d OH-C-H, OH-C-H, H-C-OH

Monosan
Monsan
Sterisan
Sensolan
Pental Sol
Sonnets
Vitessa additive

Monosan: disinfectant detergent with high washing power
Sterisan: In the vat, caustic: disinfectant and bleach for 40°C
Sensolan:
Penta-Sol: Harmful to the environment in the vat. Attention: Focus on amplifiers and degreasers
Sonnets:
Vitessa additive

90°: mops, floor cloths, tea towels, terry towels, tablecloths, chef's jackets, doctor's coats
60°: mop, floor cloths, tea towels, terry towels, chef's jackets, doctor's coats

Extra dry
Barriers
Iron damp
Lack of moisture

A cook and colored laundry
     Extra dry
     Cupboard dry+
     Cupboard dry
     iron-damp*
     iron damp **
     Lack of moisture
B Easy to care for
C Time selection

KB - Cook and colored laundry
FS - stain remover

Wash and spin
Drum drying: square with a circle inside, with 1, 2, 3 dots inside
Iron
Air dry: square without a circle, dry lying horizontally, vertical on the line
Dry Cleaning: Circle, A: All, F: Hydrocarbon, P: Perchlorethylene or Hydrocarbon
Bleaching: Triangle, with two slanting straight ones on the left: With oxygen, with Cl: With chlorine
Wet cleaning: circle with W

II: detergent
I: Prewash
Flower: softener

Hydrophobic: water repellent
Hydrophilic: Water loving
Amphiphile: Loving both

1.) Anionic surfactants
2.) Cationic surfactants
3.) Amphoteric surfactants
4.) Hermaphrodite

1.) Alkanes
2.) Alkylbenzenes
3.) Alkenes
4.) Fatty alcohols

1.) Oxidative bleach:
Oxygen, peroxides

Oxidative, bleach, reducing agent, absorbent

Tetrachloroethene, perchlorethylene: Ethene with Cl instead of H

Oxidation and reduction
Complex formation reaction
Acid base reaction
precipitation
Solid state reaction
Photochemical reaction

Molecular compounds
Salts
Organometallic compounds
Complexes

Salts: The salts are usually divided according to their anions

Chlorides, fluorides, idiodes, bromides, chlorates, iodates, (halides)
Nitrates, nitrites, amides (nitrogen)
Soulfate, Soulfide, Soulfite (sulphur)

Organic:
Alkanes, alkynes, alkynes, alkanols, alcohols
Amides, amines, hydrazines, ketones, alkanones, carboxylic acids, oxiranes, furans, epoxides, esters, ethers, amino acids, alkanals, aldehydes, aromatics

H-1
Hey - 2
Li-3
Be - 4
B-5
C-6
N-7
O-8
F-9
No - 10
Well - 11
Mg - 12

Halogens: Group 17

alkali metals
Alkaline earth metals
Transition metals
metals
Semimetals
non-metals
Lantanoids
Actionoids
Halogens
noble gases
Unknown

Liebig cooler
Bullet cooler
Snake cooler
Dimroth cooler
Double spiral cooler
Spiral cooler cooler
Corrugated tube cooler

R and S configuration

configuration
conformation

Orbitals
s and p orbitals
s1, s2 orbital
px, py, pz

PAULI principle: Each orbital can hold a maximum of 2 electrons that differ in their spin
HUND's rule: The second electrons are only added when all orbitals at their level have been filled

From H to Be there are only s orbitals
Above that px, py, pz

Hybridization state

4 outer electrons:

Lone pairs of electrons

The carbon has 6

Now I can put two electrons in s

Then four remain. But it remains, px, py, pz

Okay, then I have an electron in two p and a lone pair of electrons in pz

This is possible with non-metals

That's why there is hybridization

sp^3, sp^3, sp^3, sp^3

4x sp^3

Conformation:
- New Mann projection
- Armchair conformation: V and 60° angle, draw

Newmann: Take the front carbon atom, the one to the side and then circle and then the back one

configuration
R and S
Right and left hand
chirality center

Methyl: Me
Ethyl: Et
Chlorine: cl
Bromine: Br
4 possibilities, but only 2

Number them in order
Then add the name R and S

The numbering goes like this:

Atom with the largest atomic number: priority 1
Lowest priority atom 4

Priority: 1 largest atomic number, 4 lowest

O: Higher than C, than O ^= 1, C ^= 2


What about C?
HHH: Methyl
CHH: Ethyl

These are the residues C beats hydrogen

R and S configuration, whether clockwise or counterclockwise

R: Im
S: Against it

Elimination
substitution
addition

1 substituent = remainder
2 substituents
3...
4...

This is the number of remainders

The leftovers can be

1.) Methyl
2.) Ethyl
3.) Propyl
4.) ...
5.) R

Higher substituted: Seyzeff: elimination
Lower: Hoffman: At d
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