2024-12-16

ich habe den Code verbessert

#include <stdio.h>
#include <time.h>
#include <stdlib.h>

void expr (void);
void term (void);
void fact (void);

int main  (void) {
    time_t t;
    struct tm tm = *localtime(&(time_t){time(NULL)});


    printf ("(C) David Vajda\n");
    printf ("%s", asctime(&tm));
    printf ("Uebungen fuer Integralrechnung und Extrema\n\n");

    srand ((unsigned)time (&t));
    expr ();
    printf ("\n");
return 0;
}

void expr (void) {
        term ();
        if ((rand () % 3) == 2) {
            printf (" + ");
            expr ();
        }
return;
}
void term (void) {

        fact ();
        if ((rand () % 3) == 2) {
            printf (" * ");
            term ();

    }
return;
}
int count = 0;
void fact (void) {
    if ((rand () % 3) == 2) {
        printf ("(");
        expr ();
        printf (")");
        count++;
    }
    else
        printf ("%i*x^%i", 1+rand() % 8, rand () % 8);
return;
}

(C) David Vajda
Mon Dec 16 12:25:19 2024
Uebungen fuer Integralrechnung und Extrema

4*x^0 + (1*x^2 + 1*x^2)

= 4*x^2 + 4*x^2
= 16*x^2

F(x) = 16/3 * x^3
Intervall 2 .. 5

F(5) = 16/3 * 5^2
F(2) = 16/3 * 2^2

F(5) = 16/3 * 5^2
= 80/3

F(2) = 16/3 * 2^2
= 32/3

F(5) - F(2) = 80/3 - 32/3 = 48/3
= (45/3) + (3/3)
= (15) + 1 = 16


ein rechenfehler! Ausversehen, x^2 genommmen nicht x^3


(%i1) integrate (16*x^2, x, 2, 5);
(%o1)                              624
(%i2)


F(5) = 16/3 * 5^3
F(2) = 16/3 * 2^3

F(5) = 16/3 * 125
F(2) = 16/3 * 8

F(5) - F(2) = 2000/3 - 128/3
= 624